Half the period of a first order reaction is 1386 seconds . The specific rate constant of the reaction is :

Options

A. `0.5xx10^(-2) s^(-1)`
B. `0.5xx10^(-3)s^(-1)`
C. `5.0xx10^(-2) s^(-1)`
D. `5.0xx10^(-3) s^(-1)`

Answer

B

Explanation

(B) `t_(1//2)=(0.693)/(k) `
or `k = (0.693)/(t_(1//2))`
`= (0.693)/(1386) = 0.5 xx10^(-3) s^(-1)`