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The half life period for the first order...

The half life period for the first order reaction `XY_(2) rarr X+Y_(2)` is 10 minutes . In what period would the concentration of `XY_(2)` be reduced to 10% of the original concentration ?

A

33.2 min

B

90 min

C

120 min

D

26.3 min

Text Solution

Verified by Experts

The correct Answer is:
A

(A ) `k = (0.693)/(t_(1//2)) `
`= (0.693)/(10) = 0.0693 min^(-1)`
`t = (2.303 )/(k) "log" ([A]_(0))/(0.1[A]_(0))`
`= (2.303)/(0.0693)xx1= 33.2 `
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