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The rate of a first order reaction : R...

The rate of a first order reaction :
`R rarr P`
is `7.5xx10^(-4)` mol`L^(-1) "s"^(-1)` . The rate concentration of R is 0.5 mol `L^(-1)` . The rate constant is :

A

`2.5xx10^(-5) s^(-1)`

B

`1.5xx10^(-3)s^(-1)`

C

`4.16xx10^(-7) s^(-1)`

D

`1.50xx10^(5)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
(A) Rate `=7.5xx10^(-4) "mol L"^(-1) "min"^(-1)`
`(7.5xx10^(-4))/(60) mol L^(-1) s^(-1)`
Rate = k[R]
k = `("Rate")/([R])`
`= (7.4xx10^(-4))/(60xx0.5)`
`= 2.5 xx10^(-5)`
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