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In a first order reaction the concentrat...

In a first order reaction the concentration of the reactant decreases from 800 mol/ `dm^(3)` to 50 mol/ `dm^(3)` in `2xx10^(4)` sec . The rate constant of the reaction in `sec^(-1)` is :

A

`2xx10^(4)`

B

`3.45xx10^(-5)`

C

`1.386xx10^(-4)`

D

`2xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
C

(C ) k = `(2.303)/(t) "log" ([A]_(0))/([A])`
`k = (2.303)/(2xx10^(4))"log" (800)/(50) = 1.38 xx10^(-4) s^(-1)`
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