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For a second order reaction rate at a pa...

For a second order reaction rate at a particular time is x . If the initial concentration is tripled , the rate will become :

A

3x

B

`9x^(2)`

C

9x

D

27x

Text Solution

Verified by Experts

The correct Answer is:
C
( C ) Rate = `k[A]^(2) = x `
If conc . Is tripled i.e A = [3A]
Rate = `k[3A]^(2) = k.9[A]=x `
`:. (x)/(x)=9` i.e becomes nine times (9x)
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