A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be `k_(1)` and `k_(2)` respectively . Then

Options

A. `k_(2)=4k_(1)`
B. `k_(2)=2k_(1)`
C. `k_(2)=0.25 k_(1)`
D. `k_(2) = 0.5 k_(1)`

Answer

C

Explanation

(C ) For every `10^(@)` C rise in temperature rate constant becomes double . Therefore for `20^(@)` C rise in temperature rate constant will become 4 times i.e `k_(1)=4 k_(2) "or" k_(2) =0.25k_(1)` .