Find the domain of the function : `f(x)=sin^(-1)((log)_2x)`

Answer

`[1//2,2]`

Explanation

`f(x)=sin^(-1)(log_(2)x)`
Since the domain of `sin^(-1)x " is " [-1,1],f(x)=sin^(-1)(log_(2)x)` is defined if
`-1 le log_(2)x le 1`
or ` 2^(-1) le x le 2^(1)`
or `(1)/(2) le x le 2`
or domain`=[(1)/(2),2]`