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Range ofthe function f(x)=cos(Ksin x) is...

Range ofthe function `f(x)=cos(Ksin x)` is `[-1,1]`, then the least positive integral value of K will be

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
D
`y=cos(K sinx)`
`(cos^(-1)y)/(K)=sinx`
`implies -1 le (cos^(-1)y)/(K) le 1`
`implies -K le cos^(-1)y le K`
Now `cos ^(-1) y in [0,pi]`
`implies K=4`
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