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ax + by^(2) = cos y...

`ax + by^(2) = cos y `

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To find \(\frac{dy}{dx}\) for the equation \(ax + by^2 = \cos y\), we will differentiate both sides with respect to \(x\). ### Step-by-Step Solution: 1. **Differentiate both sides with respect to \(x\)**: \[ \frac{d}{dx}(ax + by^2) = \frac{d}{dx}(\cos y) \] ...
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