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y = cos ^(-1)((1 - x^(2))/(1+ x^(2))) 0 ...

`y = cos ^(-1)((1 - x^(2))/(1+ x^(2))) 0 lt x lt 1`

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To find the derivative of the function \( y = \cos^{-1}\left(\frac{1 - x^2}{1 + x^2}\right) \) for \( 0 < x < 1 \), we can follow these steps: ### Step 1: Substitute \( x \) with \( \tan(\theta) \) Let \( x = \tan(\theta) \). Then, we can express \( y \) in terms of \( \theta \): \[ y = \cos^{-1}\left(\frac{1 - \tan^2(\theta)}{1 + \tan^2(\theta)}\right) \] ...
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