When a charged particle of charge x C moves through a potential difference of y V, the gain in kinetic energy is equal to xy J.
An electron and an alpha partice have their masses in the ratio of 1:7200 and charges in the ratio of 1:2. If they start moving from rest through the same electrical potential difference, find the ratio of their velocities.

Explanation

(i) Given
`(m_(1))/(m_(2)) = (1)/(7200)`
and `y_(1) = y_(2)`
Total energy gained (xy) = change in kinetic energy
`((1)/(2)m(v^(2)-u^(2)))`
`u_(1) = u_(2) = 0`
`:. (v_(1)^(2))/(v^(2)) = (m_(2)x_(1)y_(1))/(m_(1)x_(2)y_(2))`
(ii) 60 : 1