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{:("Column" A ,, "Column" B), ((3x^(2) -...

`{:("Column" A ,, "Column" B), ((3x^(2) - 5)- (2x^(2) - 5 + y^(2)) ,, (a) x^(2) + xy + y^(2)) , (9x^(2) - 16y^(2) ,, (b) 2) , ((x^(3) - y^(3))/(x-y) ,, (c) (9x + 16y) (9x - 16y)) , ("The degree of " (x + 2) (x+3) ,, (d) x^(2) - y^(2)) , (,, (e) 1) , (,, (f) (3x + 4y) (3x - 4y)):}`

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To solve the problem, we need to match the expressions from Column A with the corresponding expressions in Column B. Let's go through each expression step by step. ### Step 1: Simplifying the first expression **Expression:** \( (3x^2 - 5) - (2x^2 - 5 + y^2) \) 1. Distribute the negative sign: \[ 3x^2 - 5 - 2x^2 + 5 - y^2 \] 2. Combine like terms: \[ (3x^2 - 2x^2) + (-5 + 5) - y^2 = x^2 - y^2 \] **Match:** This matches with option (d) \( x^2 - y^2 \). ### Step 2: Simplifying the second expression **Expression:** \( 9x^2 - 16y^2 \) 1. Recognize this as a difference of squares: \[ 9x^2 - (4y)^2 \] 2. Apply the difference of squares formula \( a^2 - b^2 = (a - b)(a + b) \): \[ (3x - 4y)(3x + 4y) \] **Match:** This matches with option (c) \( (9x + 16y)(9x - 16y) \). ### Step 3: Simplifying the third expression **Expression:** \( \frac{x^3 - y^3}{x - y} \) 1. Recognize this as a factorization of the difference of cubes: \[ x^3 - y^3 = (x - y)(x^2 + xy + y^2) \] 2. Cancel \( (x - y) \) from the numerator and denominator: \[ x^2 + xy + y^2 \] **Match:** This matches with option (a) \( x^2 + xy + y^2 \). ### Step 4: Finding the degree of the polynomial **Expression:** \( (x + 2)(x + 3) \) 1. Expand the expression: \[ x^2 + 3x + 2x + 6 = x^2 + 5x + 6 \] 2. Determine the degree: - The highest power of \( x \) is \( 2 \). **Match:** This matches with option (b) \( 2 \). ### Step 5: Finalizing the matches - The first expression matches with (d). - The second expression matches with (c). - The third expression matches with (a). - The fourth expression matches with (b). ### Summary of Matches: 1. \( (3x^2 - 5) - (2x^2 - 5 + y^2) \) matches with (d) \( x^2 - y^2 \). 2. \( 9x^2 - 16y^2 \) matches with (c) \( (9x + 16y)(9x - 16y) \). 3. \( \frac{x^3 - y^3}{x - y} \) matches with (a) \( x^2 + xy + y^2 \). 4. Degree of \( (x + 2)(x + 3) \) matches with (b) \( 2 \).

To solve the problem, we need to match the expressions from Column A with the corresponding expressions in Column B. Let's go through each expression step by step. ### Step 1: Simplifying the first expression **Expression:** \( (3x^2 - 5) - (2x^2 - 5 + y^2) \) 1. Distribute the negative sign: \[ 3x^2 - 5 - 2x^2 + 5 - y^2 ...
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The factors of x^(3)-x^(2)y-xy^(2)+y^(3) are (a (x+y)(x^(2)-xy+y^(2))(b)(x+y)(x^(2)+xy+y^(2))(c)(x+y)^(2)(x-y)(d)(x-y)^(2)(x+y)

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A common tangent to 9x^(2) - 16y^(2) = 144 and x^(2) + y^(2) = 9 is

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PEARSON IIT JEE FOUNDATION-EXPRESSIONS AND SPECIAL PRODUCTS -Concept Application (Level 1)
  1. The following steps are involved in finding the value of (97)^(2) by u...

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  2. The following steps are involved in finding the value of a^(4) + (1)/(...

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  3. The following steps are involved in the factorisation of x^(2) (x - y)...

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  4. {:( "Column" A ,, "Column" B) , ("If" a^(2) - b^(2) = 16 "and" a- b = ...

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  5. {:("Column" A ,, "Column" B), ((3x^(2) - 5)- (2x^(2) - 5 + y^(2)) ,, (...

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  6. Which of the following pairs is/are like terms ? (A) x " " (B) ...

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  7. Degree of 5x^(2)y + 3xy is "".

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  8. Zero of 3x - (3)/(2) is ""

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  9. If x , y , and z are variables , then x + y + z is a "".

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  10. Which of the following is not an identity ?

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  11. The zero of 2x + 3 is "".

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  12. The expanded form of (x+ y)^(2) is a "".

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  13. sqrt((256a^(4)b^(4))/(625a^(6)b^(2))) = ""

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  14. (a^(2)-b^(2))/(a-b) =

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  15. The following steps are involved in expanding (x+ 3y)^(2) . Arrange th...

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  16. The following steps are involved in finding the value of (97)^(2) by u...

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  17. The following steps are involved in finding the value of a^(4) + (1)/(...

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  18. The following steps are involved in the factorisation of x^(2) (x - y)...

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  19. Match Column A with Column B

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  20. Match Column A with Column B

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