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Write the expression for the de Broglie ...

Write the expression for the de Broglie wavelength associated with a charged particle of charge q and mass m, when it is accelerated through a potential V.

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An electron of mass m is accelerated through a potential difference of V volt. The kinetic energy acquired by the electron is given by
`(1)/(2) mv^(2) = eV`
Therefore, the speed v of the electron is `v = sqrt((2eV)/(m))`
Hence, the de Broglie wavelength of the electron is `lambda = (h)/(mv) = (h)/(sqrt(2 emV))`
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