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Three resistors of resistance 5 ohm, 3 o...

Three resistors of resistance 5 ohm, 3 ohm and 2 ohm are connected in series with 10 V battery. Calculate their effective resistance and the current flowing through the circuit.

Text Solution

Verified by Experts

`R_(1)=5Omega,R_(2)=3Omega,R_(3)=2Omega,V=10V`
`Rs=R_(1)+R_(2)+R_(3)`,
`R_(s)=5+3+2=10`, hence
`R_(s)=10Omega`
The current, `I=(V)/(R_(s))=(10)/(10)=1A`
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Knowledge Check

  • When three resistors are connected in series then the value of the effective resistance is

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    less than the individual resistance
    B
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    `n:1`
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    `1:n`
  • When three resistors are connected in parallel then the value of the effective resistance is __________

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    less than or equal to individual resistance
    B
    greater than or equal to invidiual resistance
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