Three resistors of 1`Omega`, 2 `Omega and 4Omega` are connected in parallel in a circuit. If a `1Omega` resistor draws a current of 1A, find the current through the other two resistors.

Explanation

`R_(1)=1Omega,R_(2)=2Omega,R_(3)=4Omega`, Current `I_(1)=1A`
The potential difference across the `1Omega` resistor `=I_(1)R_(1)=1xx1=1V`
since, the resistors are connected in parallel in the circuit, the same potential difference will exist across the other resistors also.
So, the current in the `2Omega` resistor, `(V)/(R_(2))=(1)/(2)=0.5A`
Similarly, the current in the `4Omega` resistor
`(V)/(R_(3))=1/4=0.25A`