Explain the parallel connection of series resistors.

Explanation

(i) Let `R_(1)` and `R_(2)` be connected in parallel to to give an effective resistance of RP1.
(ii) If you consider a connection of a set of series resistors connected in a parallel circuit, we get a parallel - series circuit.
(iii) Let `R_(1)` and `R_(2)` be connected in series to give an effective resistance of `R_(S1)`.
(iv) Silimarly, let `R_(3)` and `R_(4)` be connected in series to give an effective resistance of `R_(S2)`.
(v) Then, both of these serial segments are connected in parallel.

Using equation `R_(S)=R_(1)+R_(2)+R_(3)` we get
`R_(S)=R_(1)+R_(2)+R_(3)`
`R_(S1)=R_(1)+R_(2)`,
`R_(S2)=R_(3)+R_(4)`
Finally, using equation, `(1)/(R_(p))=(1)/(R_(1))+(1)/(R_(2))+(1)/(R_(3))` the net effective resistance is given by
`(1)/(R_("total"))=(1)/(R_(S1))+(1)/(R_(S2))`