Pure Si crystal at 300 k has `2.5 xx10^(28)` atoms `m^(-3)` it is doped by 1 ppm concentration of pentavalent element As calculate the new concentration of electrons and holes take `n_(i) =1.5 xx10^(16) m^(-3)`

Explanation

To solve the problem, we need to follow these steps:

### Step 1: Calculate the number of dopant atoms (As) in the silicon crystal.
Given that the concentration of silicon atoms is \(2.5 \times 10^{28} \, \text{atoms/m}^3\) and the doping concentration of arsenic (As) is 1 ppm (parts per million), we can calculate the number of arsenic atoms.

1 ppm means 1 arsenic atom in \(10^6\) silicon atoms. Therefore, the number of arsenic atoms can be calculated as:

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