A `2V` battery is connected across the points `A` and `B` as shown in the figure given below. Assuming that the resistance of each diode is zero in forward bias and infinity in reverse baise, the current supplied by the battery when its positive terminal is connected to `A` is

Explanation

(a) In this case positive terminal of the battery is connected to the point A. therefore
biased and offers other forward biased infinite hand diode `D_(2)` gets forward biased and offers zero biased and offers zero resistance the given circuit reduces to the equivalent circuit as shown :

(b) In this cae positive terminal of the battery B. therefore the diode `D_(1)` gets forward biased reversed biased

`:.` Current drawn from the battery
`l= (2V )/( 15 sigma) = 0.133 A`