A half wave rectifier provides DC output power of 30 W when 100 W AC power is supplied to it what will be the rectification efficiency and power efficiency

Explanation

To solve the problem of calculating the rectification efficiency and power efficiency of a half-wave rectifier, we can follow these steps:

### Step 1: Understand the Definitions
- **Rectification Efficiency (η_rect)**: This is defined as the ratio of the DC output power (P_dc) to the AC input power (P_ac), expressed as a percentage.
- **Power Efficiency (η_power)**: For a half-wave rectifier, this is defined as the ratio of the DC output power (P_dc) to the AC input power (P_ac) for half of the power cycle.

### Step 2: Identify Given Values
- DC output power (P_dc) = 30 W
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