In the Balmer series of atomic spectra of hydrogen atom, a line corresponding to wavelength 656.4 nm was obtained. Calculate the number of higher orbit from which the electron drops to produce this line.

Explanation

To solve the problem of finding the higher orbit from which the electron drops to produce the line corresponding to the wavelength of 656.4 nm in the Balmer series of the hydrogen atom, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Balmer Series**:
The Balmer series corresponds to electron transitions from higher energy levels (n2) to the second energy level (n1 = 2) in hydrogen.

2. **Use the Rydberg Formula**:
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