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The quantum number of four electrons are...

The quantum number of four electrons are given below:
I. `n=4,l=2,m_l=-2,m_s=-1/2` II. `n=3,l=2,m_l=1,m_s=+1/2`
`III. n = 4 , l =1 ,m _l=0 ,m_s=+1/2`
IV. `n=3,l=1,m_l=1,m_s=-1/2`
The correct order of their increasing energies will be

A

IV lt III lt II lt I

B

I lt II lt III lt IV

C

IV lt II lt III lt I

D

I lt III lt II lt IV

Text Solution

Verified by Experts

The correct Answer is:
C

`I(4d), II(3d), III(4p) (IV) (3p)`
Order of energies is
`IV (3p) < II (3d) < III (4p) < I(4d)`
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