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Permanganate ion reacts with bromide ion...

Permanganate ion reacts with bromide ion in basic medium to give manganese dioxide and bromate ion. Write the balanced ionic equation for the reaction.

Text Solution

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The chemical equation is :
`Mn O_4^(-) +Br^(-) rarr MnO_2 +BrO_3^(-)`
1. The skeleton equation with oxidation number of each atom is :
`overset(+7-2)(MnO_4^(-))+overset(-1)Br^(-) rarr overset(+4-2)(MnO_2)+overset(+5)BrO_3^(-)`

2. To balance increases and decrease in oxidation numbers, multiply `MnO_4^(-)` by 2.
`2MnO_4^(-)+Br^(-) rarr MnO_4^(-) rarr MnO_2+BrO_3^(-)` .
3. Balance all atoms other than H and O.
`2MnO_4^(-) +Br^(-) rarr 2MnO_2+BrO_3^(-)`
4. Since the reaction occurs in basic medium , add `PH^(-)` ions to right hand side.
`2MnO_4^(-) +Br^(-) rarr 2MnO_2+BrO_3^(-)+OH^(-)`
5. To add H atom , add `H_2O` molecules on the left hand side and equal number of `OH^-` ions on the right hand side.
`2MnO_4^(-) +Br^(-) +H_2Orarr 2MnO_2+BrO_3^(-)+OH^(-)+OH^(-)`
or , `2MnO_4^(-) +Br^(-) +H_2Orarr 2MnO_2+BrO_3^(-)+2OH^(-)`
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