The horizontal range of a projectile projected with a velocity V at angle 15° with the horizontal is 50 m. What will be its horizontal range if its angle of throw is increased by 30° keeping the velocity of throw to be the same ?

Options

A. 60 m
B. 80 m
C. 100 m
D. 140 m

Answer

C

Explanation

Here `R=u^(2)/g.2sinthetacostheta`
or `R=u^(2)/g sin2theta=u^(2)/gxxsin30^@`
`50=u^(2)/gxx1/2`
`:. U^(2)/g=100m`
When the angle is increased by `30^@` i.e. 30° +15° = 45°
Then `R=u^(2)/gsin90^@=u^(2)/g`
`:.R=u^(@)/g=100m`