A body is thrown horizontally with a velocity `sqrt(2gh)` from the top of a tower of height h. It strikes the level ground through the foot of the tower at a distance x from the tower. The value of x is :

Options

A. h
B. `h/2`
C. `2h`
D. 2 h/3

Answer

C

Explanation

Here `x=vt` Now `h=1/2g t^(2)` or `t=sqrt((2h)/g)`
Thus `x=sqrt(2gh)xxsqrt((2h)/g)=2h`