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If vec(A)=2hati + 3hatj and vec(B)=hati ...

If `vec(A)=2hati + 3hatj` and `vec(B)=hati + hatj`, then the vector component of `vec(A)` in the direction of `vec(B)` is :

A

`(hati + hatj)`

B

`2.5(hati + hatj)`

C

`2(hati + hatj)`

D

`3(hati + hatj)`

Text Solution

Verified by Experts

The correct Answer is:
B

Here component of A in the direction of `vec(B)` is
`Acostheta=((Acostheta)B)/B`
`=(ABcostheta)/B=(vec(A).vec(B))/B=(vec(A)vec(B))/B(vec(B)/B)`
`=5/sqrt(2)(hati+hatj)/sqrt(2)=2.5(hati+hatj)`
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