A projectile is given an initial velocit...

A projectile is given an initial velocity of `(hati + 2hatj)` m/s, where `hati` is along the ground and `hatj` is along the vertical. If `g = 10 m//s^(2)` , the equation of its trajectory is:

`y=2x-5x^(2)`

`4y=2x-5x^(2)`

`4y=2x-25x^(2)`

`y=x-5x^(2)`

Verified by Experts

The correct Answer is:

Here x=t
`:.y=2t-5t^(2)`
Equation of trajectory `y=2x-5x^(2)`

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