The Van't Hoff factor for 0.1 M `Ba(NO_(3))_(2)` solution is 2.74. The degree of dissociation is

Options

A. 0.913
B. 0.87
C. 1
D. 0.74

Answer

B

Explanation

`{:(,Ba(NO_(3))_(2),hArr,Ca^(2+) +2NO_(3)^(-),),(" Initial",1 "mol",," - - ",),("After dissociation",1-alpha,,alpha " " 2alpha,):}`
Total moles `= 1- alpha+alpha+2alpha=1+2alpha`
`i=1+2alpha " or " alpha=(i-1)/(2)=(2.74-1)/(2)=0.87` or 87%.