What volume of 36 N and 1N sulphuric acid must be mixed to get 1L of 6N sulphuric acid

Options

A. 96.7 ml of 36 N + 903.3 ml of 1N
B. 142.8 ml of 36 N + 857.2 ml of 1N
C. 903.3 ml of 36 N + 96.7 ml of 1N
D. 100 ml of 36 N + 900 ml of 1N

Answer

B

Explanation

Let volume of 36 N `H_(2)SO_(4)=x` litre and volume of `1 N H_(2)SO_(4)=(1-x)` litre.
Both these acids on mixing should give 6 equivalents of `H_(2)SO_(4)`
`:.36x+(1-x)=6` or `35x=5`
or `x=(5)/(35)=1/7 L=(1000 ml)/(7)=142.8`ml
`:.` 142.8 ml of 36N `H_(2)SO_(4)` and 857.2 ml of 1N `H_(2)SO_(4)` should be mixed.