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A 0.0020 M aqueous solution of an ionic ...

A 0.0020 M aqueous solution of an ionic compound `Co(NH_(3))_(4)(NO_(2))_(2)Cl` freeze at - `0.00732^(@)C`. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be `(K_(f)=1.86^(@)C//m)`.

A

3

B

4

C

1

D

2

Text Solution

Verified by Experts

The correct Answer is:
D

The number of moles produced by 1 mole of ionic compound
`DeltaT_(f)=iK_(f)m, i=DeltaT_(f)//K_(f)m`
`DeltaT_(f)=0-(-0.00732)`
`=0.00732^(@)C`
`K_(f)=1.86^(@)C//m`
`m=0.0020`
`i=(0.00732)/(1.86xx0.0020)`
`=1.96~~2`
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