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The amount of solute ( molar mass 60 g "...

The amount of solute ( molar mass 60 g `"mol"^(-1)` ) that must be added to 180 g of water so that the vapour pressure of water is lowered by 10% is

A

30 g

B

60 g

C

120 g

D

12 g

Text Solution

Verified by Experts

The correct Answer is:
B
`(p_(A)^(@)-p_(A))/(p_(A)^(@))=(w_(B)M_(A))/(w_(A)M_(B))`
`:.(10)/(100)=(w_(B)xx18)/(180xx60)`
`:.w_(B)=(10)/(100)xx(180xx60)/(18)=60g`
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