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3g of urea is dissolved in 45g of H(2)O....

3g of urea is dissolved in 45g of `H_(2)O`. The relative lowering in vapour pressure is

A

0.05

B

0.04

C

0.02

D

0.01

Text Solution

Verified by Experts

The correct Answer is:
C
Relative lowering of vapour pressure,
`(p_(A)^(@)-p_(A))/(p_(A)^(@))=x_(B)`
where `x_(B)` is the mole fraction of solute (urea)
`x_("urea")=(n_("urea"))/(n_("urea")+n_(H_(2)O))~~(n_("urea"))/(n_(H_(2)O))` (for dilute solutions)
`n_("urea")=(3)/(60)=0.05`
`n_(H_(2)O)=(45)/(15)=2.5`
`n_("urea")=(0.05)/(2.5)=0.02`
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