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Find (dy)/(dx) when : y=x^(8)/8-x^(6)/...

Find `(dy)/(dx)` when :
`y=x^(8)/8-x^(6)/6+x^(4)/4-2`

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The correct Answer is:
To find \(\frac{dy}{dx}\) for the function \[ y = \frac{x^8}{8} - \frac{x^6}{6} + \frac{x^4}{4} - 2, \] we will differentiate each term of the function with respect to \(x\). ### Step 1: Differentiate each term 1. **Differentiate \(\frac{x^8}{8}\)**: - Using the power rule, \(\frac{d}{dx}(x^n) = nx^{n-1}\): \[ \frac{d}{dx}\left(\frac{x^8}{8}\right) = \frac{1}{8} \cdot 8x^{8-1} = x^7. \] 2. **Differentiate \(-\frac{x^6}{6}\)**: - Again using the power rule: \[ \frac{d}{dx}\left(-\frac{x^6}{6}\right) = -\frac{1}{6} \cdot 6x^{6-1} = -x^5. \] 3. **Differentiate \(\frac{x^4}{4}\)**: - Using the power rule: \[ \frac{d}{dx}\left(\frac{x^4}{4}\right) = \frac{1}{4} \cdot 4x^{4-1} = x^3. \] 4. **Differentiate \(-2\)**: - The derivative of a constant is 0: \[ \frac{d}{dx}(-2) = 0. \] ### Step 2: Combine the derivatives Now, we combine the results from the differentiation: \[ \frac{dy}{dx} = x^7 - x^5 + x^3 + 0. \] Thus, we can simplify this to: \[ \frac{dy}{dx} = x^7 - x^5 + x^3. \] ### Final Answer The derivative \(\frac{dy}{dx}\) is: \[ \frac{dy}{dx} = x^7 - x^5 + x^3. \] ---
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