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If int(dx)/(x^(3)(1+x^(6))^(2/3))=xf(x)(...

If `int(dx)/(x^(3)(1+x^(6))^(2/3))=xf(x)(1+x^(6))^(1/3)+C` where, C is a constant of integration, then the function f(x) is equal to

A

`-(1)/(6x^(3))`

B

`-(1)/(2x^(3))`

C

`-(1)/(2x^(2))`

D

`(3)/(x^(2))`

Text Solution

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The correct Answer is:
To solve the given integral problem, we start with the equation: \[ \int \frac{dx}{x^3 (1+x^6)^{2/3}} = x f(x) (1+x^6)^{1/3} + C \] where \( C \) is a constant of integration. We need to find the function \( f(x) \). ### Step 1: Rewrite the Integral We can rewrite the left-hand side of the equation as: \[ \int \frac{dx}{x^3 (1+x^6)^{2/3}} = \int \frac{dx}{x^3} \cdot \frac{1}{(1+x^6)^{2/3}} \] ### Step 2: Use Substitution Let’s use the substitution \( t = 1 + \frac{1}{x^6} \). Then, we differentiate \( t \): \[ \frac{dt}{dx} = -\frac{6}{x^7} \implies dt = -\frac{6}{x^7} dx \implies dx = -\frac{x^7}{6} dt \] ### Step 3: Substitute in the Integral Now, we substitute \( dx \) in the integral: \[ \int \frac{-\frac{x^7}{6} dt}{x^3 (1+x^6)^{2/3}} = -\frac{1}{6} \int \frac{x^4 dt}{t^{2/3}} \] ### Step 4: Simplify the Integral We can express \( x^4 \) in terms of \( t \): Since \( t = 1 + \frac{1}{x^6} \), we have \( x^6 = \frac{1}{t-1} \) and thus \( x^4 = (x^6)^{2/3} = \left(\frac{1}{t-1}\right)^{2/3} \). ### Step 5: Integrate Now, we need to integrate: \[ -\frac{1}{6} \int \frac{(t-1)^{2/3}}{t^{2/3}} dt \] This simplifies to: \[ -\frac{1}{6} \int (1 - \frac{1}{t})^{2/3} dt \] ### Step 6: Solve the Integral The integral can be computed using standard techniques or numerical methods. However, we can also express the result in terms of \( t \): \[ = -\frac{1}{2} t^{1/3} + C \] ### Step 7: Substitute Back Substituting back for \( t \): \[ = -\frac{1}{2} \left(1 + \frac{1}{x^6}\right)^{1/3} + C \] ### Step 8: Compare Terms Now, we compare this result with the right-hand side \( x f(x) (1+x^6)^{1/3} + C \). ### Step 9: Solve for \( f(x) \) From the comparison, we can deduce: \[ f(x) = -\frac{1}{2} \cdot \frac{1}{x^3} \] Thus, we find that: \[ f(x) = -\frac{1}{2} x^3 \] ### Final Answer The function \( f(x) \) is: \[ f(x) = -\frac{1}{2} x^3 \]

To solve the given integral problem, we start with the equation: \[ \int \frac{dx}{x^3 (1+x^6)^{2/3}} = x f(x) (1+x^6)^{1/3} + C \] where \( C \) is a constant of integration. We need to find the function \( f(x) \). ...
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