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When 5 is added to the numerator and den...

When 5 is added to the numerator and denominator both of a (positive) fraction , then the new ratio of numerator to denominator becomes 11:15. What is the original ratio?

A

`17:25`

B

`3:5`

C

`28:40`

D

None of these

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The correct Answer is:
To solve the problem, we need to find the original ratio of a fraction given that when 5 is added to both the numerator and the denominator, the new ratio becomes 11:15. Let's denote the original numerator as \( x \) and the original denominator as \( y \). ### Step-by-step Solution: 1. **Set up the equation based on the problem statement:** When 5 is added to both the numerator and the denominator, the new fraction becomes: \[ \frac{x + 5}{y + 5} = \frac{11}{15} \] 2. **Cross-multiply to eliminate the fraction:** Cross-multiplying gives us: \[ 15(x + 5) = 11(y + 5) \] 3. **Expand both sides:** Expanding both sides results in: \[ 15x + 75 = 11y + 55 \] 4. **Rearrange the equation:** Rearranging the equation to isolate terms gives us: \[ 15x - 11y = 55 - 75 \] \[ 15x - 11y = -20 \] 5. **Express one variable in terms of the other:** We can express \( y \) in terms of \( x \): \[ 15x + 20 = 11y \] \[ y = \frac{15x + 20}{11} \] 6. **Find integer values for \( x \) and \( y \):** Since \( x \) and \( y \) must be integers, we can test integer values for \( x \) to find a corresponding integer \( y \). Let's try \( x = 1 \): \[ y = \frac{15(1) + 20}{11} = \frac{35}{11} \quad \text{(not an integer)} \] Try \( x = 2 \): \[ y = \frac{15(2) + 20}{11} = \frac{50}{11} \quad \text{(not an integer)} \] Try \( x = 3 \): \[ y = \frac{15(3) + 20}{11} = \frac{65}{11} \quad \text{(not an integer)} \] Try \( x = 4 \): \[ y = \frac{15(4) + 20}{11} = \frac{80}{11} \quad \text{(not an integer)} \] Try \( x = 5 \): \[ y = \frac{15(5) + 20}{11} = \frac{95}{11} \quad \text{(not an integer)} \] Try \( x = 6 \): \[ y = \frac{15(6) + 20}{11} = \frac{110}{11} = 10 \quad \text{(is an integer)} \] 7. **Determine the original ratio:** Now we have \( x = 6 \) and \( y = 10 \). Therefore, the original ratio of the fraction is: \[ \frac{x}{y} = \frac{6}{10} = \frac{3}{5} \] ### Final Answer: The original ratio of the fraction is \( 3:5 \).
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