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If the ratio of diagonals of two cubes i...

If the ratio of diagonals of two cubes is 3:2 then the ratio of the surface areas of the two cubes respectively is :

A

`5:4`

B

`9:5`

C

`9:4`

D

can't be determined

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the surface areas of two cubes given the ratio of their diagonals. Let's break it down step by step. ### Step 1: Understand the relationship between the diagonal and the side of a cube. The formula for the diagonal (d) of a cube with side length (s) is given by: \[ d = s \sqrt{3} \] ### Step 2: Set up the ratio of the diagonals. Given that the ratio of the diagonals of two cubes is \( \frac{3}{2} \), we can express this as: \[ \frac{d_1}{d_2} = \frac{3}{2} \] Where \( d_1 \) is the diagonal of Cube 1 and \( d_2 \) is the diagonal of Cube 2. ### Step 3: Substitute the formula for the diagonals. Using the formula for the diagonal, we can write: \[ \frac{s_1 \sqrt{3}}{s_2 \sqrt{3}} = \frac{3}{2} \] Here, \( s_1 \) and \( s_2 \) are the side lengths of Cube 1 and Cube 2 respectively. ### Step 4: Simplify the equation. The \( \sqrt{3} \) cancels out: \[ \frac{s_1}{s_2} = \frac{3}{2} \] ### Step 5: Find the ratio of the surface areas. The surface area (A) of a cube is given by: \[ A = 6s^2 \] Thus, the ratio of the surface areas of the two cubes is: \[ \frac{A_1}{A_2} = \frac{6s_1^2}{6s_2^2} = \frac{s_1^2}{s_2^2} \] ### Step 6: Substitute the ratio of the sides. From the ratio of the sides, we have: \[ \frac{s_1}{s_2} = \frac{3}{2} \] Now, squaring both sides gives: \[ \left(\frac{s_1}{s_2}\right)^2 = \left(\frac{3}{2}\right)^2 = \frac{9}{4} \] ### Step 7: Conclude the ratio of the surface areas. Thus, the ratio of the surface areas of the two cubes is: \[ \frac{A_1}{A_2} = \frac{9}{4} \] ### Final Answer: The ratio of the surface areas of the two cubes is \( 9:4 \). ---
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