A light of wavelength 6000 `Å` , in air, enters, a medium with refractive index 1.5. Inside the medium, its frequency is `"________________"` Hz and its wavelength is `"________________" Å`

Explanation

Since `v=(c)/(lambda)=(3 xx 10^(8))/(5000 xx 10^(-10))=0.6 xx 10^(15)`
`=6 xx 10^(14)`
Frequency is the fundamental property and hence does not change when light enters another medium.