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A pendulum is hung from the roof of a su...

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 `m//s^(2)` at a distance of 5 m from the mean position. The time period of oscillation is

A

2s

B

`pis`

C

`2pis`

D

1s

Text Solution

Verified by Experts

The correct Answer is:
B
`|a| = omega^(2)x`
`rArr 20 = omega^(2)`
`rArr omega = 2rad//s`
`T = (2pi)/(omega) = (2pi)/(2) = pis`
Hence option (b) is correct.
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