`20%N_(2)O_(4)` molecules are dissociated in a sample of gas at `27^(@)C` and 760 torr. Calculate the density of the equilibrium mixture.

Options

A. `3.1 gL^(-1)`
B. `6.2 gL^(-1)`
C. `12.4 gL^(-1)`
D. `18.6 gL^(-1)`

Answer

A

Explanation

`{:(,N_(2)O_(4),hArr,2NO_(2)),("Initial conc.",1,,0),("At equilibrium",1-0.20,,0.40):}`
`"Mol.wt. of mixture"=(0.80xx92+0.4xx46)/(1.2)`
`=76.66`
`"Now "rho=(pM)/(RT)=(1xx76.66)/(0.082xx300)=3.1gL^(-1)`