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The RMS velocity of CH(4) will become do...

The RMS velocity of `CH_(4)` will become double its value at STP when the temperature is :

A

546 K

B

`819^(@)C`

C

`546^(@)C`

D

819 K

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The correct Answer is:
To find the temperature at which the RMS velocity of \( CH_4 \) (methane) becomes double its value at Standard Temperature and Pressure (STP), we can follow these steps: ### Step 1: Understand the RMS Velocity Formula The formula for the root mean square (RMS) velocity (\( v_{rms} \)) of a gas is given by: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \] where: - \( R \) is the universal gas constant, - \( T \) is the temperature in Kelvin, - \( M \) is the molar mass of the gas. ### Step 2: Identify the Molar Mass of \( CH_4 \) The molar mass of methane (\( CH_4 \)) can be calculated as follows: - Carbon (C) has a molar mass of approximately 12 g/mol. - Hydrogen (H) has a molar mass of approximately 1 g/mol, and there are 4 hydrogen atoms in methane. Thus, the molar mass \( M \) of \( CH_4 \) is: \[ M = 12 + (4 \times 1) = 16 \, \text{g/mol} \] ### Step 3: Determine the RMS Velocity at STP At STP, the temperature \( T \) is 273 K. Plugging this value into the RMS velocity formula gives: \[ v_{rms, STP} = \sqrt{\frac{3R \cdot 273}{16}} \] ### Step 4: Set Up the Equation for Double the RMS Velocity We want to find the temperature \( T' \) at which the RMS velocity is double that at STP: \[ v_{rms, T'} = 2 \cdot v_{rms, STP} \] Substituting the expression for \( v_{rms} \): \[ \sqrt{\frac{3R T'}{16}} = 2 \cdot \sqrt{\frac{3R \cdot 273}{16}} \] ### Step 5: Simplify the Equation Squaring both sides to eliminate the square root gives: \[ \frac{3R T'}{16} = 4 \cdot \frac{3R \cdot 273}{16} \] The \( \frac{3R}{16} \) cancels out: \[ T' = 4 \cdot 273 \] ### Step 6: Calculate the New Temperature Calculating \( T' \): \[ T' = 4 \cdot 273 = 1092 \, \text{K} \] ### Step 7: Convert to Celsius To convert from Kelvin to Celsius: \[ T'_{Celsius} = 1092 - 273 = 819 \, \text{°C} \] ### Final Answer The temperature at which the RMS velocity of \( CH_4 \) becomes double its value at STP is: - **1092 K** or **819 °C**. ---

To find the temperature at which the RMS velocity of \( CH_4 \) (methane) becomes double its value at Standard Temperature and Pressure (STP), we can follow these steps: ### Step 1: Understand the RMS Velocity Formula The formula for the root mean square (RMS) velocity (\( v_{rms} \)) of a gas is given by: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \] where: ...
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