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The temperature at which hydrogen molecu...

The temperature at which hydrogen molecules have the same kinetic energy as oxygen molecules have at `40^(@)C` is :

A

`40^(@)C`

B

`5^(@)C`

C

`320^(@)C`

D

`640^(@)C`

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The correct Answer is:
To solve the problem, we need to determine the temperature at which hydrogen molecules have the same kinetic energy as oxygen molecules at 40°C. ### Step-by-Step Solution: 1. **Understand the Kinetic Energy Formula**: The kinetic energy (KE) of a gas is given by the formula: \[ KE = \frac{3}{2} RT \] where \( R \) is the universal gas constant and \( T \) is the temperature in Kelvin. 2. **Convert the Given Temperature to Kelvin**: The temperature of oxygen is given as 40°C. To convert this to Kelvin, we use the formula: \[ T(K) = T(°C) + 273.15 \] Therefore, \[ T(O_2) = 40 + 273.15 = 313.15 \, K \] 3. **Set the Kinetic Energies Equal**: Since we want the kinetic energy of hydrogen (\( KE_{H_2} \)) to be equal to that of oxygen (\( KE_{O_2} \)), we can write: \[ KE_{H_2} = KE_{O_2} \] This means: \[ \frac{3}{2} R T_{H_2} = \frac{3}{2} R T_{O_2} \] Since \( R \) and \( \frac{3}{2} \) are constants and will cancel out, we have: \[ T_{H_2} = T_{O_2} \] 4. **Conclusion**: Therefore, the temperature at which hydrogen molecules have the same kinetic energy as oxygen molecules at 40°C is: \[ T_{H_2} = 313.15 \, K \] To express this in Celsius: \[ T_{H_2} = 313.15 - 273.15 = 40°C \] ### Final Answer: The temperature at which hydrogen molecules have the same kinetic energy as oxygen molecules at 40°C is **40°C**.
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MODERN PUBLICATION-STATES OF MATTER : GASES AND LIQUIDS-COMPETITION FILE OBJECTIVE TYPE QUESTIONS (A. MULTIPLE CHOICE QUESTIONS)
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