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The rms velocity of hydrogen is sqrt(7) ...

The rms velocity of hydrogen is `sqrt(7)` times the rms velocity of nitrogen. If `T` is the temperature of the gas, then

A

`T(H_(2))=T(N_(2))`

B

`T(H_(2))gtT(N_(2))`

C

`T(H_(2))ltT(N_(2))`

D

`T(H_(2))=sqrt7(N_(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

`u=sqrt((3RT)/(M))`
`(m(H_(2)))/(u(N_(2)))=sqrt((T(H_(2)))/(M(H_(2)))xx(M(N_(2)))/(T(N_(2))))`
`sqrt7=sqrt((T(H_(2)))/(T(N_(2)))xx(28)/(2))`
`7=(T(H_(2)))/(T(N_(2)))xx14`
`T(N_(2))=2T(H_(2))`
`"i.e. "T(N_(2))gtT(H_(2))`
`"or "T(H_(2))ltT(N_(2))`
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