What will happen to volume of a bubble of air found under water in a lake where temperature is `15^(@)C` and the pressure is 1.5 atm, if the bubble rises to the surface where the temperature is `25^(@)C` and the pressure is 1.0 atm?

Options

A. Its volume will become greater by a factor of 2.5
B. Its volume will become greater by a factor of 1.6
C. Its volume will become greater by a factor of 1.1
D. Its volume will become greater by a factor of 0.70

Answer

B

Explanation

`(p_(1)V_(1))/(T_(1))=(p_(2)V_(2))/(T_(2))`
`p_(1)="1.5 atm"`
`T_(1)=15^(@)C=(15+273)K=288K`
`p_(2)="1.0 atm"`
`T_(2)=25^(@)C=(25+273)K=298K`
`therefore" "(1.5xxV_(1))/(288)=(1xxV_(2))/(298)`
`therefore" "V_(2)=(V_(1)xx298xx1.5)/(288)=1.55V_(1)~~1.6V_(1)`