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The mass of 2.24xx10^(-3)m^(3) of a gas ...

The mass of `2.24xx10^(-3)m^(3)` of a gas is 4.4 g at 273.15 K and 101.325 Kpa pressure. The gas may be

A

NO

B

`NO_(2)`

C

`C_(3)H_(8)`

D

`NH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`V=2.24xx10^(-3)m^(3)=2.24L`
`m=4.4g`
`T=273.15K`
`p=101.325kPa`
`=101325 Pa=1atm`
`pV=nRT or pV=(m)/(M)RT`
`therefore" 1 atm "xx2.24L=(4.4g)/(M)xx"0.0821 L atm K"^(-1)"mol"^(-1)xx273.15K`
`therefore" "M="44.05 g mol"^(-1)`
Therefore, the gas is `C_(3)H_(8)`
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