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A block of mass m is placed on another b...

A block of mass m is placed on another block of mass M lying on a smooth horizontal surface as shown in the figure. The co-efficient of friction between the blocks is `mu`. Find the maximum horizontal force F (in Newton) that can be applied to the block M so that the blocks together with same acceleration? `(M=3kg, m=2kg, mu=0.1, g=10m//s^(2))`

Text Solution

Verified by Experts

When both blocks move together `a=(F)/(M+m)`
From FBD of m relative to M for both blocks to move together

`ma lt f`
`m((F)/(M+m))lt mu mg`
`F lt (M+m)mu mg`
`F lt (M+m) mu g`
`F lt 5N`
`therefore F_("max")=5N`
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Knowledge Check

  • A block of mass m is placed on another block of mass M which itself is lying on a horizontal surface .The coefficient of friction between two blocks is mu_(1) and that between the block of mass M and horizontal surfece is mu_(2) What maximum horizontal force can be applied to the lower block move without separation?

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    `(M +m) (mu_(2) - mu_(1))g`
    B
    `(M - m) (mu_(2) - mu_(1))g`
    C
    `(M - m) (mu_(2) + mu_(1))g`
    D
    `(M +m) (mu_(2) + mu_(1))g`
  • A block of mass m is placed on the top of another block of mass M as shown in the figure. The coefficient of friction between them is mu . The maximum acceleration with which the block M may move so that m also moves along with it is

    A
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    B
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    C
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    B
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    C
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