In Wacker oxidation of ethene, the product formed is

Options

A. Ethanoic acid
B. Ethanal
C. Ethanol
D. Ethanedial

Answer

To solve the question regarding the product formed in the Wacker oxidation of ethene, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant**: The reactant in this case is ethene, which has the molecular formula C2H4. It can be represented as CH2=CH2.

2. **Understand the Wacker Oxidation Process**: The Wacker oxidation involves the oxidation of alkenes to carbonyl compounds (aldehydes or ketones) using palladium(II) chloride (PdCl2) as a catalyst in the presence of water.

3. **Reaction Mechanism**: In the case of ethene, the double bond is oxidized. The first step converts ethene into an intermediate, which is then further oxidized. The oxidation of ethene leads to the formation of acetaldehyde (ethanal), which has the structure CH3CHO.

4. **Identify the Product**: After the Wacker oxidation, the product formed from ethene is acetaldehyde (ethanal).

5. **Conclusion**: Therefore, the product formed in the Wacker oxidation of ethene is acetaldehyde (ethanal).

### Final Answer:
The product formed in the Wacker oxidation of ethene is **acetaldehyde (ethanal)**.

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