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If A=[[cosalpha,sinalpha],[-sinalpha,cos...

If `A=[[cosalpha,sinalpha],[-sinalpha,cosalpha]]`, find `'alpha'` satisfy- ing `0ltalphalt(pi)/(2)` when `A+A^(tau)=sqrt(2)I_(2)`, where `A^(tau)` is transpose of A.

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The correct Answer is:
`alpha=pi/4`
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