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int (cos 4x-1)/(cot x-tanx)dx equals :...

`int (cos 4x-1)/(cot x-tanx)dx` equals :

A

`-(1)/(4)cos 4x+c`

B

`-(1)/(2)cos 4x+c`

C

`-(1)/(2)sin 2x+c`

D

None of these.

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • int (cos4x+1)/(cotx-tanx) dx = A cos 4x + B then

    A
    A =-1/2
    B
    A =-1/8
    C
    A= -1/4
    D
    none of these

  • int (cos 2x-1)/(cos 2x+1) dx =

    A
    tan x - x + c
    B
    x + tan x + c
    C
    x- tan x + c
    D
    minus x - cot x + c

  • If (1+cos 4x)/(cot x-tan x) dx = A cos 4x + B , then the values of A and B are

    A
    `A = 1/8, B in R`
    B
    `A = -1/8, B in R`
    C
    `A = 1/4, B in R`
    D
    none of these

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    int (1+cos 2x)/(1-cos 2x) dx =

    int (sin 4x)/(cos 4x) dx =

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