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Orbital speed of a satellite...

Orbital speed of a satellite

A

decreases with increase in height of satellite.

B

is independent of the mass of satellite.

C

is along the tangent to the orbital path of satellite.

D

is independent of the mass and radius of the planet around which the revolution of satellite takes place.

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The correct Answer is:
To find the orbital speed of a satellite, we need to derive the formula based on the forces acting on the satellite. Here’s a step-by-step solution: ### Step 1: Understanding the Forces A satellite in orbit around a planet experiences gravitational force, which provides the necessary centripetal force for its circular motion. The gravitational force acting on the satellite is given by Newton's law of gravitation. ### Step 2: Write the Gravitational Force Equation The gravitational force \( F_g \) acting on the satellite can be expressed as: \[ F_g = \frac{G \cdot M \cdot m}{r^2} \] where: - \( G \) is the universal gravitational constant, - \( M \) is the mass of the planet, - \( m \) is the mass of the satellite, - \( r \) is the distance from the center of the planet to the satellite. ### Step 3: Write the Centripetal Force Equation For an object in uniform circular motion, the centripetal force \( F_c \) required to keep the satellite in orbit is given by: \[ F_c = \frac{m \cdot v^2}{r} \] where: - \( v \) is the orbital speed of the satellite. ### Step 4: Set the Forces Equal Since the gravitational force provides the centripetal force, we can set these two equations equal to each other: \[ \frac{G \cdot M \cdot m}{r^2} = \frac{m \cdot v^2}{r} \] ### Step 5: Cancel Out the Mass of the Satellite We can cancel the mass of the satellite \( m \) from both sides of the equation (assuming \( m \neq 0 \)): \[ \frac{G \cdot M}{r^2} = \frac{v^2}{r} \] ### Step 6: Solve for Orbital Speed Now, multiply both sides by \( r \) to isolate \( v^2 \): \[ \frac{G \cdot M}{r} = v^2 \] Taking the square root of both sides gives us the formula for the orbital speed \( v \): \[ v = \sqrt{\frac{G \cdot M}{r}} \] ### Step 7: Analyze the Result From the derived formula \( v = \sqrt{\frac{G \cdot M}{r}} \), we can analyze how the orbital speed depends on various factors: 1. **Height of the Satellite**: As the height increases (which increases \( r \)), the orbital speed \( v \) decreases. 2. **Mass of the Satellite**: The mass \( m \) of the satellite does not appear in the final formula, indicating that the orbital speed is independent of the satellite's mass. 3. **Mass of the Planet**: The orbital speed depends on the mass \( M \) of the planet. 4. **Radius**: The orbital speed depends on the radius \( r \) from the center of the planet. ### Conclusion The orbital speed of a satellite decreases with an increase in height, is independent of the mass of the satellite, and is dependent on the mass of the planet and the radius of the orbit. ---
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