Home
Class 9
PHYSICS
If the length of a seconds pendulum on...

If the length of a seconds pendulum on a planet is 2 m then the acceleration due to gravity on the surface of that planet is `"______"` (Take the acceleration due to gravity on the surface of the Earth =9.8 `m s^(-2)`)

Promotional Banner

Topper's Solved these Questions

  • MEASUREMENTS

    PEARSON IIT JEE FOUNDATION|Exercise Shor answer type Question|14 Videos

  • MEASUREMENTS

    PEARSON IIT JEE FOUNDATION|Exercise Essay Type questions|5 Videos

  • MEASUREMENTS

    PEARSON IIT JEE FOUNDATION|Exercise Level 3|8 Videos

  • MAGNETISM

    PEARSON IIT JEE FOUNDATION|Exercise Level-3|10 Videos

  • MODERN PHYSICS

    PEARSON IIT JEE FOUNDATION|Exercise Level 3|5 Videos

Similar Questions

Explore conceptually related problems

How is the length of seconds pendulum related with acceleration due to gravity of any planet?

The acceleration due to gravity is 9.8m//s^(2)

Given, acceleration due to gravity on surface of earth is g. if g' is acceleration due to gravity at a height h above the surface of earth, then

The acceleration due to gravity is _____ at the surface of the earth and ____ at the centre of the earth.

The time period of a pendulum on the surfacce of the moon is 5s. If it is a seconds pendulum on earth and the acceleratio due to gravity on the earth is 9.8 m s^(-2) , find the acceleration due to gravity on the surface of the moon.

Calculate the acceleration due to gravity at a height of 1600 km from the surface of the Earth. (Given acceleration due to gravity on the surface of the Earth g_(0) = 9.8 ms^(-2) and radius of earth, R = 6400 km).