Pendulum A is x cm shorter than a seconds pendulum and pendulum B is x cm longer than the seconds pendulum . The ratio of their time periods is `3: 4` . The length of the pendulum with higher frequency is

Options

A. 86 cm
B. 114 cm
C. 128 cm
D. 72 cm

Answer

A

Explanation

Units of Surface Tension `=N m^(-1)`
work `xx` volume `xx` speed `=(N m) xx (m^(3)) xx m s^(-1)`
`=N m^(5) s^(-1)`
`("work " xx " velocit ")/("volume ")= ((N m ) xx (m s^(-1))/(m^(3)) =Nm^(-1)s^(-1)`
`(" work" xx "velocity")/(" rateof change of volume") =((Nm)xx(ms^(-1)))/(m^(3)) =N m^(-1)s^(-1)`
`("work")/("time") xx (" volume")/("velocity") =(Nm)/(s^(-1)) xx (m^(3))/(ms^(-1)) =N m^(3) s^(2)`